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For the reaction shown, find the limiting reactant for each of the following initial amounts of reactants. 4Cr(s)+3O2(g)→2Cr2O3(s)Part A: 1 molCr; 1 molO2 Express your answer as a chemical formula. Part B: 4 molCr; 2.5 molO2 Express your answer as a chemical formula. Part C: 12 molCr; 10 molO2 Express your answer as a chemical formula. Part D: 14.8 molCr; 10.3 molO2 Express your answer as a chemical formula.
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