a stone is thrown from the top of a 78.4 m high cliff with an upward velocity component of 19.6 m/sec how is the stone in the air
y = vo.t + a.t22 78.4m = −19.6m/s ∗ t + 9.8m/s2 .t22 clearing for t−4.9. ∗ t2 + 19.6 ∗ t + 78.4 = 0 second grade equationa = −4.9b = 19.6c = 78.4t1 = 6.47st2 = −2.47s the time…
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