Dear Tutor,Can I have a solution of this problem?======================================================The position function x(t) of a particle moving along an x axis is x = 6.00 – 8.00t2, with x in meters and t in seconds. (e) To shift the curve rightward on the graph, should we include the term +20t (denote 1) or the term -20t (denote 0) in x(t)? (f) Does that inclusion increase (denote 1) or decrease (denote 0) the value of x at which the particle momentarily stops?
x = 6.00 – 8.00t2e) X is parabola pointing downwards and intersecting the t axis at Now add 20t to the function X.X = 6+20t-8t2And plot the graph. From the graph you can observe that the graph…
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