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January 1, 2018 312 Final Exam tlace the code to show how you reached the answer. (3 points) int i = 10; t of the following C code fragment. You must Write your answer here. while (i 3) f i=i-1; if(i%2== 1) continue; printf(**In”); if (i == 4) break;

Hi,
Output=
***
***
***
***
Explanation:
The code starts with intial value of i=10;
In the next line, we have one ‘while’ loop.
Iteration 1-
It evaluates the condition if i>=3. The condition is true. So the control goes inside the while loop. Now ‘i=i-1’ decrements the value of i by 1. So now i=9. Now if i%2==1 is true as 9%2==1 is true so the loop continues in the loop. In the next step, print ‘***’. In the next step value of i is again decremented to 1 so new value of i=8. In the next line condition 8==4 is false so the loop starts over again.
Console status-
***
Iteration 2-
It evaluates the condition if i>=3. As 8>=3, the condition is true. So the control goes inside the while loop. Now ‘i=i-1’ decrements the value of i by 1. So now i=7. Now if i%2==1 is true as 7%2==1 is true so the loop continues in the loop. In the next step, print ‘***’. In the next step value of i is again decremented to 1 so new value of i=6. In the next line condition 6==4 is false so the loop starts over again.
Console status-
***
***
Iteration 3-
It evaluates the condition if i>=3. As 6>=3, the condition is true. So the control goes inside the while loop. Now ‘i=i-1’ decrements the value of i by 1. So now i=5. Now if i%2==1 is true as 5%2==1 is true so the loop continues in the loop. In the next step, print ‘***’. In the next step value of i is again decremented to 1 so new value of i=4. In the next line condition 4==4 is true so the control comes out of the loop
Console status-
***
***
***
Iteration 4-
It evaluates the condition if i>=3. As 4>=3, the condition is true. So the control goes inside the while loop. Now ‘i=i-1’ decrements the value of i by 1. So now i=3. Now if i%2==1 is true as 3%2==1 is true so the loop continues in the loop. In the next step, print ‘***’. In the next step value of i is again decremented to 1 so new value of i=2. In the next line condition 2==4 is false so the control comes out of the loop
Console status-
***
***
***
***
 
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