a) Construct probability table.
Number of breakdowns Number of years in which breakdowns occurred Frequency
0 4 22.22%
1 3 16.67%
2 1 5.56%
3 5 27.78%
4 5 27.78%
5 0 0%
18
(a) Expected number of breakdowns per year = 0*22.22%+1*16.67%+2*5.56%+3*27.78%+4*27.78%+5*0% = 2.22
(b) The cost of current maintenance policy is $ 5000 per year.
(c) Expected cost of failure = Expected number of failures per year * Cost of each failure = 2.22*2000 = $ 4444 per year
We see that the expected cost of failures is less than the cost of current maintenance policy. Therefore, the more economic policy is to get corrective maintenance based on actual failures, rather than having a service contract for $ 5000. In this case, the expected cost will be $ 4444 per year.
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