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5) Consider the array called myArray declared below that contains positive and negative integers. Write a loop statement to count and display the number of integers in the array that are divisible by 3. That is, your loop should display the message “Number of integers divisible by 3 is 2” (4 points) int myArray[]s( 1,3,9,9 1,40,4,5, 100.20,-23); Note: The loop should always work without modification even if the values in the array are changed https://media.cheggcdn.com/media%2Fe4e%2Fe4e62247-b5c5-40ff-beb0-90d65a054700%2Fimage

ANSWER 1:
SOURCE CODE:
#include
using namespace std;
int main()
{
int size,counter=0;
int myArray[]={1,3,9,91,40,4,-5,100,20,-23};
size=sizeof(myArray)/sizeof(myArray[0]);
cout
 
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