Posted on by Judy

A tourist center is open on weekends (Friday, Saturday, and Sunday). The owner-manager hopes to improve scheduling of part-time employees by determining seasonal relatives for each of these days. Data on recent traffic at the center have been tabulated and are shown in the following table: Week 1 2 3 4 5 6 Friday 142 152 152 152 157 162 Saturday 252 252 262 262 277 277 Sunday 162 162 172 172 172 182 a. Develop seasonal relatives for the shop using the centered moving average method. (Round your intermediate calculations and final answers to 2 decimal places.) X¯¯¯X¯ Friday = Saturday = Sunday = b. Develop seasonal relatives for the shop using the SA method. (Round your intermediate calculations and final answers to 4 decimal places.) SA Index Friday = Saturday = Sunday =

b. Average demand = Sum of all values / no. of monts in the sample = 195.6
Ratio for friday (Week 1) = Demand / Avg. demand = 142/ 195.6 = 0.72
Ratio for week 2 = 152 /195.6 = 0.77
Ratio for week 3 = 152 /195.6 = 0.77
Ratio for week 4 = 152 /195.6 = 0.77
Ratio for week 5 = 157 /195.6 = 0.8
Ratio for week 6 = 162 / 195.6 = 0.82
Avg ratio for friday = Ratios from week 1 to 6 / 6 = 77.5
Similarly Avg ratio for Saturday = 2(252 /195.6 ) + 2 ( 262 / 195.6) + 2( 277/195.6) /6
= 2.57 +2.67 +2.83 /6 = 1.34
Avg Ratio for sunday = 2 ( 162 /195.6) + 3 ( 172/ 195.6) + 182/195.6 /6
= 1.64 +2.63 +0.93 /6 = 0.86
a.
Wk Traffic MA5 Tr. / MA5
F 142
S 252
S 162 192 0.84
F 152 196 0.77
S 252 176 1.43
S 162 196 0.82
F 152 200 0.76
S 262 180 1,45
S 172 200 0.86
F 152 204 0.74
S 262 183 1.43
S 172 204 0.84
F 157 208 0.75
S 277 188 1.47
S 172 209 0.82
F 162 214 0.75
S 277
S 182
Avg Friday = 3.77/5 = 0.74
Avg Saturday = 4.33/4 = 1.44
Avg. Sunday = 4.18 / 5 = 0.836
 
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