##f(x)=x^3-5x^2+x-5##
I have assumed that ##{5,i,-i}## are intended to be the of the function.
In this case, the function can be factored as:##color(white)(“XXX”)(x-5)((x-i)(x+i)##
##color(white)(“XXX”)=(x-5)(x^2-i^2)##
##color(white)(“XXX”)=(x-5)(x^2+1)##
##color(white)(“XXX”)=x^3+x -5x^x-5##
(or in standard polynomial form)##color(white)(“XXX”)=x^3-5x^2+x-5##
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