Posted on by Judy

Which plant had the highest labor productivity? Japan in 2013 Japan in 2014 USA in 2013 USA in 2014 Which plant had the highest total productivity (include all inputs)? Japan in 2013 Japan in 2014 USA in 2013 USA in 2014 Which of the following is closest to the value for percent change in labor productivity for Japan from 2013 to 2014? 3% -2% 5% 1% Which plant experienced the best change in total productivity from 2013 to 2014? Japan USA A manufacturer has designed a product. This product has four components (Components A, B, C, and D). The reliability probabilities associated with each product are: A: 0.9 B: 0.75 C: 0.8 D: 0.6 a) What is the probability that this product will be reliable? b) The manufacturer can afford to modify the product to incorporate redundancy in one of the components. Which of the components should be selected and why? c) If component C were to receive a redundant backup with a reliability probability of 0.6, what would be the reliability of the product? What would be the failure probability? d) If each component were to receive a redundant backup with a reliability probability of 0.5, what would be the reliability of the product? What would be the failure probability?

Answer (a) The probability that this product will be reliable = p(A)*p(B)*p(C)*p(D)
= (0.90) *(0.75) *(0.80) *(0.60) = 0.32
Answer (b) Component D should be selected as it has the lowest reliability probability value and most likely to be unsuccessful.
Answer (c) =>Finding the new reliability of component C:
For Component C to be reliable then the probability = 1 – (probability of component C getting unsuccessful or fail) = 1 – (probability of component C and failed redundant backup)
= 1 – [(1- 0.8) *(1- 0.6)] = 1 – [(0.2) *(0.4)] = 1 – 0.08 = 0.92
Hence, probability for the reliable product = (0.9) *(0.75) *(0.92) *(0.6) = 0.37
Therefore, the failure probability = 1 – 0.37 = 0.63
Answer (d) => Finding the new reliabilities for each component:
For component A => 1- [(1-0.90) * 0.5] = 1 – (0.1) *(0.5) = 0.95
For component B => 1- [(1-0.75) * 0.5] = 1 – (0.25) *(0.5) = 0.875
For component C => 1- [(1-0.8) * 0.5] = 1 – (0.2) *(0.5) = 0.9
For component D => 1- [(1- 0.6) * 0.5] = 1 – (0.4) *(0.5) = 0.8
Hence, the reliability of product = (0.95) * (0.875) * (0.9) * (0.8) = 0.599
Therefore, the failure probability = 1 – 0.599 = 0.401
===================================================================================
For the questions mentioned on labour productivity, Input values are not available in the question.
However, Labor productivity should be evaluated using output and input ( = Output / Input)
 
“Looking for a Similar Assignment? Get Expert Help at an Amazing Discount!”

What Students Are Saying About Us

.......... Customer ID: 12*** | Rating: ⭐⭐⭐⭐⭐
"Honestly, I was afraid to send my paper to you, but splendidwritings.com proved they are a trustworthy service. My essay was done in less than a day, and I received a brilliant piece. I didn’t even believe it was my essay at first 🙂 Great job, thank you!"

.......... Customer ID: 14***| Rating: ⭐⭐⭐⭐⭐
"The company has some nice prices and good content. I ordered a term paper here and got a very good one. I'll keep ordering from this website."

"Order a Custom Paper on Similar Assignment! No Plagiarism! Enjoy 20% Discount"

Related posts:

  1. Which of the following is closest to the value for percent change in labor productivity for Japan from 2013 to 2014? 3% -2% 5% 1% Which plant experienced the best change in total productivity from 2013 to 2014? Japan USA A manufacturer has designed a product. This product has four components (Components A, B, C, and D). The reliability probabilities associated with each product are: A: 0.9 B: 0.75 C: 0.8 D: 0.6 a) What is the probability that this product will be reliable? b) The manufacturer can afford to modify the product to incorporate redundancy in one of the components. Which of the components should be selected and why? c) If component C were to receive a redundant backup with a reliability probability of 0.6, what would be the reliability of the product? What would be the failure probability? d) If each component were to receive a redundant backup with a reliability probability of 0.5, what would be the reliability of the product? What would be the failure probability?
  2. What is the reliability that bank loans will be processed accurately if each of the five clerks shown in the chart has the reliability shown? What is the reliability that bank loans will be processed accurately if each of the five clerks shown in the chart has the reliability shown? https://d2vlcm61l7u1fs.cloudfront.net/media%2F6c0%2F6c0d7329-f35b-4a27-9a3e-f7dfc16da25f%2Fphp9n7eaB.png Bookshelf Onl × Chapter 5 Exe e Financial Stat x e The Controlle x-e The Records- x-e For Each Of TX · Stgtealh Secure | https://online.vitalsource.com/#/books/9780134616322/cfi/6/1 6481/4/2/6/16/2/4/2@0:78.9 ::: Apps「ASUS E Service fn Yorkville Education Iran021.net Iran Vl[ 『J Serial Eshgh az no t Netflix 1 Serial Pikar tars 1 脂 Serial Daste sarneve 17.9 What is the reliability that bank loans will be processed accurately if each of the five clerks shown in the chart has the reliability shown? 0.95 0.95 0.95 0.95 0.95 17.10 Merril Kim Sharp has a system composed of three components in parallel. The components have the following reliabilities: R.-0.90, R2-0.95, R3-0.85
  3. The Sentry Lock Corporation manufactures a popular commercial security lock at plants in Macon, Louisville, Detroit, and Phoenix. The per unit cost of production at each plant is $35.50, $37.50, $39.00, and $36.25, respectively, and the annual produc- tion capacity at each plant is 18,000, 15,000, 25,000, and 20,000, respectively. Sentry’s locks are sold to retailers through wholesale distributors in seven cities across the United States. The unit cost of shipping from each plant to each distributor is sum- marized in the following table along with the forecasted demand from each distrib- utor for the coming year. Unit Shipping Cost to Distributor in Plants Tacoma San Diego Dallas Denver St. Louis Tampa Baltimore Macon $2.50 $2.75 $1.75 $2.00 $2.10 $1.80 $1.65 Louisville $1.85 $1.90 $1.50 $1.60 $1.00 $1.90 $1.85 Detroit $2.30 $2.25 $1.85 $1.25 $1.50 $2.25 $2.00 Phoenix $1.90 $0.90 $1.60 $1.75 $2.00 $2.50 $2.65 Demand 8,500 14,500 13,500 12,600 18,000 15,000 9,000 Sentry wants to determine the least expensive way of manufacturing and shipping locks from their plants to the distributors. Because the total demand from distribu- tors exceeds the total production capacity for all the plants, Sentry realizes it will not be able to satisfy all the demand for its product, but wants to make sure each dis- tributor will have the opportunity to fill at least 80% of the orders they receive. a. Create a spreadsheet model for this problem and solve it. b. What is the optimal solution? c. Is the solution unique? d. If Sentry wants to increase their production capacity to meet more of the demand for their product, which plant should they use? Explain. e. If the cost of shipping from Phoenix to Tacoma increased to $1.98 per unit, would the solution change? Explain. f. Could the company make more money if they relaxed the restriction that each distributor must receive at least 80% of the predicted demand? Explain. g. How much extra should the company charge the distributor in Tacoma if this distributor insisted on receiving 8,500 units?
  4. The Sentry Lock Corporation manufactures a popular commercial security lock at plants in Macon, Louisville, Detroit, and Phoenix. The per unit cost of production at each plant is $35.50, $37.50, $39.00, and $36.25, respectively, and the annual produc- tion capacity at each plant is 18,000, 15,000, 25,000, and 20,000, respectively. Sentry’s locks are sold to retailers through wholesale distributors in seven cities across the United States. The unit cost of shipping from each plant to each distributor is sum- marized in the following table along with the forecasted demand from each distrib- utor for the coming year. Unit Shipping Cost to Distributor in Plants Tacoma San Diego Dallas Denver St. Louis Tampa Baltimore Macon $2.50 $2.75 $1.75 $2.00 $2.10 $1.80 $1.65 Louisville $1.85 $1.90 $1.50 $1.60 $1.00 $1.90 $1.85 Detroit $2.30 $2.25 $1.85 $1.25 $1.50 $2.25 $2.00 Phoenix $1.90 $0.90 $1.60 $1.75 $2.00 $2.50 $2.65 Demand 8,500 14,500 13,500 12,600 18,000 15,000 9,000 Sentry wants to determine the least expensive way of manufacturing and shipping locks from their plants to the distributors. Because the total demand from distribu- tors exceeds the total production capacity for all the plants, Sentry realizes it will not be able to satisfy all the demand for its product, but wants to make sure each dis- tributor will have the opportunity to fill at least 80% of the orders they receive. a. Create a spreadsheet model for this problem and solve it. b. What is the optimal solution? c. Is the solution unique? d. If Sentry wants to increase their production capacity to meet more of the demand for their product, which plant should they use? Explain. e. If the cost of shipping from Phoenix to Tacoma increased to $1.98 per unit, would the solution change? Explain. f. Could the company make more money if they relaxed the restriction that each distributor must receive at least 80% of the predicted demand? Explain. g. How much extra should the company charge the distributor in Tacoma if this distributor insisted on receiving 8,500 units?